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Problem 3: A. Two very thin spherical shells y un spherical shells (Figa re arra

ID: 2292864 • Letter: P

Question

Problem 3: A. Two very thin spherical shells y un spherical shells (Figa re arranged concentrically. inner shell has radius a=3 mm, the outer, ras as radius a-3 mm, the outer radius b 9 mm. Half the space between the shells is filled with air wh e shells is filled with air while the other half is filled with water The air permittivity between the the shells is s=480. Calculate the capacitan capacitance between the two shells). Fig. B Fig. A 4TTE C = tivity between the shells is 60. The water permittivity between e the capacitance of the device (i.e. the P = por Clear all;clc; %part a a=3e-3;b=9e-3; epso=8.85; in pico eps=4 *epso; C air= C water- C=C_air+C_water %Find C_air %Find C_H20 B. In Fig. B, calculate the self-inductance L of 10 cm of coaxial cable wit a=0.8 mm and b = 4 mm, filled with material for which ur = 30; clear all; clc; a=0.8e-3; b=4e-3; L=10e-2; mu 0=0.4*pi; %in milli mur=30; %in mH L=

Explanation / Answer

Part A code:

clear all;
clc;
%%part a%%
a=3e-3; b=9e-3;
eps0=8.85e-12;
eps=4*eps0;
C_air= (4*pi*eps0)/((1/a)-(1/b))
C_water= (4*pi*eps)/((1/a)-(1/b))
C=C_air+ C_water


Part A output:

C_air =

   5.0046e-13


C_water =

   2.0018e-12


C =

   2.5023e-12

Part B code:

clear all;
clc;
%%part b%%
a=0.8e-3; b=4e-3; l=10e-2;
mu=0.4*pi*1e-6;
mur=30;
Inductance_L=((mu*mur*l)/(2*pi))*log(b/a)


part B output:

Inductance_L =

   9.6566e-07 or 0.96566e-0.6 H

NOTE: %% there is a small mistake in code for part B. mu0 is in micro units not in milli units thus why the

final answer is in micro H not in milli H..%%

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