Fundamentals of High Voltage Engineering . In an experiment for determining the
ID: 2294179 • Letter: F
Question
Fundamentals of High Voltage Engineering . In an experiment for determining the breakdown strength of transformer oil with standard electrodes, the following observations were obtained with two different types of oils. Determine the power law for breakdown and hence estimate the breakdown strength for a 1 cm gap Gap spacing (mm) BD voltage (kV) Gap spacing (mm) BD voltage (kV) 6 148 6 143 10 219 12 214 A oil 86 3 84 169 9 192 B oil (Answers: A oil: V-32.6d4, BDS 210 kV/cm; B oi: Vb 31.4d0.82, BDS- 204 kV/em) 2. An insulator is composed of two parallel connected plane insulators with their plates area of 0.2 dm2 The two materials have relative permittivity as 4 and 2.7 and with loss angles (dissipation angles) ?? 4.6° and 62-5.7°. Electrode distance is 3 mm. If the insulator operates at VRMs 20 kV at 50 Hz, which of the two materials will suffer from thermal breakdown earlierExplanation / Answer
x1=[3 6 9 10]; % oil 1
y1=[86 148 169 219];
p1 = polyfit(log(x1),log(y1),1); % y=b*x^m'
m1= p1(1)
b1= exp(p1(2))
y1_1cm_oil_1=b1*(10)^m1 %1cm BDS
x2=[3 6 9 12]; %oil 2
y2=[84 143 192 214];
p2 = polyfit(log(x2),log(y2),1);
m2 = p2(1)
b2 = exp(p2(2))
y2_1cm_oil_1=b2*(10)^m2 % 1cm BDS
Solution from matlab
>> HVwork
m1 =
0.7066
b1 =
39.9280
y1_1cm_oil_1 =
39.9280
m2 =
0.6926
b2 =
40.1729
y2_1cm_oil_1 =
40.1729
>> HVwork
m1 =
0.7066
b1 =
39.9280
y1_1cm_oil_1 =
203.1984
m2 =
0.6926
b2 =
40.1729
y2_1cm_oil_1 =
197.9186
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second part electrode type is not mentioned
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