How...? Please show your work. Thanks.. A bat strikes a 0.145-kg baseball. Just

Question

How...? Please show your work. Thanks..

A bat strikes a 0.145-kg baseball. Just before impact, the ball is traveling horizontally to the right at 40.0m/s , and it leaves the bat traveling to the left at an angle of 40? above horizontal with a speed of 60.0m/s . The ball and bat are in contact for 1.85ms

Find the horizontal component of the average force on the ball. Take the x-direction to be positive to the right Express your answer using two significant figures. Find the vertical component of the average force on the ball. Express your answer using two significant figures.

Explanation / Answer

before impact

Pix = m*u = 0.145*40 = 5.8 kg m/s.......Piy = 0

after impact
Pfx = -m*V*cos40 = -0.145*60*cos40 = -6.66 kg m/s

Pfy = m*V*sin40 = 0.145*60* sin 40 = 5.59 kg m/s

F x = Pfx - Pix/t = (-6.66 - 5.8) /(1.85*10^-3) = ?6735.14 N

Fy = (Pfy - Piy) /t = 5.59/(1.85*10^-3) = 3021.62 N

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