A DC voltage source provides a voltage V = 12.0Vand is connected to a resistor o

Question

A DC voltage source provides a voltage V = 12.0Vand is connected to a resistor of resistance R = 150? and an ideal inductor with inductance L, forming the circuit shown in the figure. (Figure 1) For a long time, the switch has been in the position shown, so that a constant current has been built up in the circuit by the voltage source. At t=0 the switch is thrown open to remove the voltage source from the circuit. At time t after t=0, the current through the inductor and the voltage across the inductor are given by, respectively, I(t) and V(t).

What is the current I(?) that flows through the inductor one time constant after the voltage source is removed?

Express your answer in amperes.

Explanation / Answer

I(t) = 12/150 * e^(-t/c), where c = time constant

Ans = I(one_time_constant) = 12/150 * e^(-1) = 0.02943 A

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