Detailed answer please. Easy 1500 A cat is located 4.7 m in front of a concave m
ID: 2299726 • Letter: D
Question
Detailed answer please. Easy 1500
A cat is located 4.7 m in front of a concave mirror. The mirror has a radius of 1.9 m. Construct a ray diagram to scale following the steps outlined in the procedure here.
(a) Where is the image of the cat?
(b) Is this image real or virtual?
(c) If the image of the cat is 4.5 cm tall, how tall is the cat?
cm
An object 7.0 cm tall is 35 cm in front of a convex mirror with a radius of curvature of 35 cm.
(a) Construct a ray diagram to scale following the steps outlined in the procedures here. Indicate the parallel, focal, and central rays in your diagram
(b) Where is the image?
(c) Is the image real or virtual?
How big is it?
cm
Explanation / Answer
apply for concave miriror, 1/f = 1/u +1 /v
here f = R/2 = 1.90/2 = 0.95 m
so v = uf/u-f
v = 0.85* 4.7/(4.7 -0.95)
v = 1.063 m
it is areal image
magnificatiom m = -v/u
m = -1.062/4.7= -0.226
so image height = -0.226* 4.5 = 1.02 cm , inverted image
2. apply for convex mirror, -1/f = 1/u +1/v
here f = R/2 = 35/2 = 17.5 cm
v = uf/(-u-f)
v = 35* 17.5/( -17.5-35)
v = -11.667 cm is the image distance from lens
so magnifuication m = -v/u
m = -(-11.667)/35 = 0.334
so image height Y' = 0.334* 7 = 2.338 cm
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