I\'M HAVING A HARD TIME WORKING THIS PROBLEMS OUT. I\'VE ALREADY RESEARCHED THE
ID: 2301785 • Letter: I
Question
I'M HAVING A HARD TIME WORKING THIS PROBLEMS OUT.
I'VE ALREADY RESEARCHED THE INTERNET FOR POSSIBLE ANSWERS.
A simple pendulum consisting of a 20 g mass has initialangular displacement of 8.0o. It oscillates with aperiod of 3.00s.
a. Determine the length of the pendulum
b. Does the period of the pendulum depend on the initialangular displacement
c. Does the period of the pendulum depend on the mass of thependulum
d. Does the period of the pendulum depend on the lengthof the pendulum
e. Does the period of the pendulem depend on the accelerationdue to gravity
Explanation / Answer
A) time period is T = 2*pi*sqrt(L/g*cos theta)...
length of the pendulum is L = [T/2*pi]^2*(g cos theta) = [3/(4*3.142)]^2*9.8*cos 8 = 0.55m.....
from the formula time period is T = 2*pi*sqrt(L/g*cos theta)...
Time period dends upon the initialangular displacement
period of the pendulum depend on the lengthof the pendulum
period of the pendulem depend on the accelerationdue to gravity
period of the pendulum does not depend on the mass of thependulum
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