A child, hunting for his favorite wooden horse, is running on the ground around

Question

A child, hunting for his favorite wooden horse, is running on the ground around the edge of a
stationary merry-go-round. The angular speed of the child has a constant value of 0.253
rad/s. A child, hunting for his favorite wooden horse, is running on the ground around the edge of a
stationary merry-go-round. The angular speed of the child has a constant value of 0.253
rad/s. (in the direction the child is running) with a constant angular
acceleration of 0.0139 rad/s2. What is the shortest time it takes for the child to catch up with
the horse? (use 3 sig figs in final answer).

Explanation / Answer

assume the child does not do the sensible thing and just step onto the merry go round and walk to her horse.

Let t be the time when child and horse are adjacent

0.253t = ?/2 +

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