In scuba diving, a regulator is used so that the pressure of the air the diver b

Question

In scuba diving, a regulator is used so that the pressure of the air the diver breathes is close to that of the ambient water. A reckless swimmer decides to use a hose sticking out of the surface to breathe underwater while diving in a lake. When the air pressure in the lungs is at a pressure of around
0.115 atmospheres below the ambient
pressure, lung injury may occur. Find the depth at which the swimmer would experience such a pressure differential.

I need a correct final answer at the end in order to give full rating. Thanks.

Explanation / Answer

Pressure at a Depth of h

P=Po+pgh

Differential Pressure

dP=P-Po=pgh

Given

dP=0.115 atm

since 1 atm =1.013*105 pascals

dP=0.115*1.013*105=11649.5 Pascals

and Density of water

p=1000 Kg/m3

so

=>11649.5=1000*9.8*h

h=1.189 m=1.19 m( approx)

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