? Part A Constants At an instant when the charge on the capacitor is 0.060 ,C, w

Question

? Part A Constants At an instant when the charge on the capacitor is 0.060 ,C, what is the current in the inductor? A 6.70-nF capacitor is charged to 24.0 V then disconnected from the battery in the circuit and connected in series with a coil that has L 0.0610 H and negligible resistance. After the circuit has been completed, there are current oscillations. Express your answer with the appropriate units. i= 1 Value Units Submit ? Part B How much energy is stored in the capacitor? Express your answer with the appropriate units UC =10.26 . 10-6 IJ

Explanation / Answer

In LC circuit ,Enenrgy remain constant

T=initial Energy=0.5*C*V^2=1.9296*10^(-6)

(a)When Q=0.06 uC,Energy of C=E=0.5*Q^2/C=0.268*10^(-6)

Energy of inductor=T-E=0.5*L*I^2

I=7.38*10^(-3) A

Part (b)

E=0.268uJ=2.68*10^(-7) J

part (c)

I=T-E=1.66*10^(-6) J

part (d)

q=Qcos(wt)

Q=6.7*10^(-9)*24=0.1608 uC

if q=0.06uC

cos(wt)=0.3731

w=sqr(1/LC)=49875.46

i=Isin(wt)

I=7.95*10^(-3)

di/dt=Iwcos(wt)=149.05 A/s

part E

V=Q/C=8.96 V

part F

V=Ldi/dt=9.028

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