1) If you inject 200 MBq of F into the body in the form of FDG, how many atoms o

Question

1) If you inject 200 MBq of F into the body in the form of FDG, how many atoms of will you have after 24 hours given that decays into the stable nuclide lor The half-life of 1 is 1.83 hours. atoms Submit 3) Assuming you start with 1 mCi ofe and no 3n, what will the activity of 52Mn be after 10 min? Answer in mCi mCi Submit 4) What will be the activity in previous question after 20 minutes? mCi Submit 5) When will the activity of the sample be the highest, i.e. when is the best time to elute the sample? min Submit 6) Over the weekend there is no one working to elute the sample. Assuming you start [ with 1010 Bg of 52e and no 52Mn, what will the activity of 52Mn be after 48 hours? Bq Submit 7) What is the activity of the Fe in Question 6 at this point? Bq Submit

Explanation / Answer

solving 1st question

(1) We know that

activity is given as

A=A0e^(-ln(2)*t/t(1/2))

we know t1/2=1.83 hours

Ao=200 MBq

so we got

A=0.0225MBq

So activity is 0.0225MBq

No of atom=A/decay constant

decay constant=ln(2)/t1/2=1.052*10^(-4)

so No of atom=2.14*10^(8) atoms

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