help for this problem please thanks. Chapter 14, Problem 011 Flying Circus of Ph

Question

help for this problem please thanks.

Chapter 14, Problem 011 Flying Circus of Physics Giraffe bending to drink. In a giraffe with its head 2.25 m above its heart, and its heart 2.05 m above its feet, the(hydrostatic) gauge pressure in the blood at its heart is 272 gauge) blood pressure (a) at the brain (the pressure is enough to perfuse the brain with blood, to keep the giraffe from fainting) and (b) at the feet (the pressure must be countered by tight-fittin stocking). (c) If the giraffe were to lower its head to drink from a pond without splaying its legs and movi brain? (Such action would probably be lethal.) slowly, what would be the increase in the blood pressure in the (a) Number (b) Number Units (c) Number Units

Explanation / Answer

Given

Density of blood = 1060 kg/m3

A)For The Head :-

Height above heart = 2.23 m ; g = 10m/s2

So pressure diff wrt heart = (density)*g*h= (1060)(10)(2.25) = 23850 Pa

Now 1 atm = 1.01*10^5 Pa = 760 Torr => 1 Pa = 7.5*10^-3 torr

23638 Pa = 178.875 torr less

pressure at head = 272 - 177.3 = 93.125 Torr (ans)

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B) Height below heart = 2.05 m

Pressure increase = (1060)(10)(2.05)(7.5*10^-3) Torr = 162.975 Torr

Thus pressure at feet = 272 + 146.28 = 434.98 Torr (ans)

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C) Pressure in head = Pressure in leg = 434.98 Torr

or increase in pressure in Head = (434.98 - 93.125) = 341.86 Torr (ans)

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