An object is 1.6 m to the left of a lens of focal length 0.6 m. A second lens of

Question

An object is 1.6 m to the left of a lens of focal length 0.6 m. A second lens of focal length -2.9 m is 0.5 m to the right of the frst lens. Find the distance betiween the object and the final image formed by the second lens m Enter 2 s ponz 0 attempt(s) made (maximum allowed for credit-5) ater that, ultiply credit by 0.5 up to 10 attempts] What is the overall magnification (with sign)? Enter 2 s pona 0 attempt(s) made (maximum allowed for credit-5) after that, multply credit by d5 up to 10 attempt:] Is the final image real or virtual? 1. Oreal 2. virtual Enter 2 pon 0 attempt(s) made (maximum allowed for credit-1) Is it upright or inverted? 1. upright 2 inverted Enter [2.3 points] 0 attempt(s) made (maximum allowed for credit = 1)

Explanation / Answer

for first lens,

f1 = 0.6 m

p1 = 1.6 m

1/f = 1/p + 1/q

1/0.6 = 1/1.6 + 1/q1

q1 = 0.96 m

for second lens,

object distance, p2 = 0.5 - 0.96 = - 0.46 m

f2 = - 2.9 m

1/(-2.9) = 1/ (-0.46) + 1/q2

q2 = 0.55 m

distance between object and final image

= 1.6 + 0.5 + 0.55

= 2.65 m ......Ans

m = (q1/p1)(q2/p2) = (0.55 / -0.46) (0.96/1.6)

m = - 0.72 .......Ans

Image is real

m is -ve so image is inverted.

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