A proton with the initial velocity of 2 0 ? 1 0 6 m / s along the x - direction
ID: 2305097 • Letter: A
Question
A proton with the initial velocity of
2
0
?
1
0
6
m
/
s
along the x
-
direction enters a uniform
magnetic field of magnitude B=0.3T with a direction perpendicular to the proton’s
velocity. It leaves the field
-
filled region with a velocity
?
2
0
?
1
0
6
m
/
s
in the y
-
direction.
(a) Determine the direction of the magnetic field, (b) the radius of curvature of the
proton’s trajectory while in the field, (c) the distance the proton travelled in the field, and
(d) the time interval during whic
h the proton is in the field.
Explanation / Answer
A. As given in the question, field is perpendicular to proton's velocity. Magnetic field will be in z-direction. Perpendicular to xy-plane.
B. The Proton's trajectory will be hyperbola.
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