A converging lens, which has a focal length equal to 9.2 cm, is separated by 31.

Question

A converging lens, which has a focal length equal to 9.2 cm, is separated by 31.8 cm from a second lens. The second lens is a diverging lens that has a focal length equal to -13.4 cm. An object is 18.4 cm to the left of the first lens.

(a) Find the position of the final image using both a ray diagram and the thin-lens equation.
cm to the right of the object

(c) What is the overall lateral magnification?

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An object is 19.5 cm to the left of a lens that has a focal length of +8.50 cm. A second lens, which has a focal length of -28.0 cm, is 4.80 cm to the right of the first lens.

(a) Find the distance between the object and the final image formed by the second lens.
cm

(b) What is the overall magnification?

Explanation / Answer

2.

From thin lens equation

1/f =1/S1 + 1/S1'

For First lens ,Location of the image formed by the first lens

1/8.5 =1/19.5 + 1/S1'

S1' =15.07 cm

Since second lens is 4.8 cm to the right of first lens

S2=4.8-15.07 =-10.27 cm

Now

1/f2 =1/S2 + 1/S2'

-1/28 = -1/10.27 +1/S2'

S2' =16.22 cm

b)

Magnification

M=m1m2 =(-S1'/S1)(-S2'/S2) =(15.07/19.5)(16.22/-10.27)

M=1.22

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