A Hollow conducting sphere has an inner radius of 15 cm, an outer radius of 32 c

ID: 2307145 • Letter: A

Question

A Hollow conducting sphere has an inner radius of 15 cm, an outer radius of 32 cm, and an excess charge of +6.5 mC

a) What is the surface charge density of the sphere

b) Set up the eq to determine the electric field 17 cm from the center of the sphere (don't solve)

c) What if b was non-conduting?

d) What is the electric field 22 cm from the center of the sphere? 48?

e) What is the electric FLUX 48 cm from the center of the sphere? 12?

f) What is the electic potential 100 cm from the center of the sphere? Use ref electric potential of zero volts at infinity

Surface charge density is calculated as follows:

charge density= Q/A = Q/4*pi*r^2

substitute the numerical data in above equation and solve for charge density.

the electric field is calculated as follows:

E (at 0.17 m) = kq/r^2

= [knA]/r^2

= [kn(4(pi)R^2)]/r^2

substitute the numerical data in above equation and solve for electric field.

it will be zero when it is non-conducting.

the electric field at R < r is zero in this case. So, the electric field is zero at r = 22 cm

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