A constant horizontal pull acts on a sled on a horizontal frictionless ice pond.

Question

A constant horizontal pull acts on a sled on a horizontal frictionless ice pond. The sled starts from rest. When the pull acts over a distance x, the sled acquires a speed v and a kinetic energy K. If the same pull instead acts over twice this distance: The sled's speed will be v squareroot 2 and its kinetic energy will be K squareroot 2. The sled's speed will be v squareroot 2 and its kinetic energy will be 2K. The sled's speed will be 2v and its kinetic energy will be K squareroot2. The sled's speed will be 2v and its kinetic energy will be 2K. The sled's speed will be 2v and its kinetic energy will be 4K.

Explanation / Answer

Let the force is F.

So worl done by force = F*x

SO KE= F*x

Vlocity = (2*F*x/m)^1/2

NOw if distance is doubled then KE would be doubled and V would be 2^1/2 times. so second option is answer

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