The figure (Figure 1) shows a small plant near a thin lens. The ray shown is one

Question

The figure (Figure 1) shows a small plant near a thin lens. The ray shown is one of the principal rays for the lens. Each square is 2.2 cm along the horizontal direction, but the vertical direction is not to the same scale. Use information from the diagram to answer the following questions:

Part A

Using only the ray shown, decide what type of lens this is.

Using only the ray shown, decide what type of lens this is.

converging

Part B

What is the focal length of the lens?

Express your answer using two significant figures.

Part C

Calculate where the image should be.

converging

Part B

What is the focal length of the lens?

Express your answer using two significant figures.

Part C

Calculate where the image should be.

Express your answer using two significant figures.

Explanation / Answer

The lens is diverging , therefore the rays which become parallel to optical axis must be moving along a direction which meets to the focus ( in real or virtual way)

Thus focal length =3×2.2 cm = 6.6 cm

Part B

f = -6.6 cm

u= -6.6. cm

v = uf/(u+f) = -3.3 cm

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