What is the live load if this floor is to be used in a typical residential dwell
ID: 2311062 • Letter: W
Question
What is the live load if this floor is to be used in a typical residential dwelling?
(I'm a little confused on this question? Is there a formula for live loads? or do i just put what the chart says below? Ive included the dead load with my calculations in case you need it)
Total weight is 6.4lb
Volume of a 1-ft-long joist = 0.14ft^3
Using the density of Douglas fir, which is 34lb
Weight of a 1-ft-long joist = (0.14) (34) = 4.8lb
A 1-ft-long floor joist carries 1.33ft^2 of floor
The weight of floor joist that contributes to 1ft^2 of the floor is 4.8 / 1.33 = 3.6lb
The total dead load of 1ft^2 of floor is 6.4lb + 3.6lb = 10lb
Residential dwellings Dwellings and hotel guest rooms 40 Habitable attics 30 Corridors, public spaces, and balconies 100Explanation / Answer
The permanent dead load calculated is okk...to calculate the imposed dead and imposed live load we should follow the given table or assume some appropriate values accordingbto the given conditions....since we have the floor is given ,we should simple multiply the imposed uniformly dead load and uniformly live load with joist floor area and sum up the all to calculate the total loads on the joist...
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.