We build a multiplier for two 4-bit unsigned integers A=(A3A2A1A0) and B=(B3B2B1

Question

We build a multiplier for two 4-bit unsigned integers A=(A3A2A1A0) and B=(B3B2B1B0)...

4. [Total 5 pts] In this question, we build a multiplier for two 4-bit unsigned integers A=(A3A2A1Ao) and B=(B3B2B,Bo). Figure 1 shows the arithmetic of this multiplication. Figure 2 shows an incomplete circuit that implements this multiplication. (For simplicity, only the relevant logical components are shown.) Ai (value of A) B Bo (value ofBI B3 2 .intermediat2) intermediate 3) A 2 B A A B intermediate 2) intermediate 4) .Xi. Xs.. Xs .X

Explanation / Answer

a)

The maximum number of significant bit resulting from AxB =11111111=256

b)

D0=A0*B0;D1=A1*B0;D2=A2*B0;D3=A3*B0;

D4=A0*B1;D5=A1*B1;D6=A2*B1;D7=A3*B1;

D8=A0*B2;D9=A1*B2;D10=A2*B2;D11=A3*B2;

D12=A0*B3;D13=A1*B3;D14=A2*B3;D15=A3*B3;

d)Carry out most signigicant bit of fulladder 3 is 0, since the maximum vlaue of resulatnt products of two four Bit number is 8 bits. the fulladder3 resulting 8 bit sum output. so the carry out always is zero.

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