Please show all work for thumbs up. Answer: ?p/?gh , D / d , ?p = 37.4 lb/ft2 1.

Question

Please show all work for thumbs up. Answer: ?p/?gh , D / d , ?p = 37.4 lb/ft2

1. When a drop of liquid falls onto a flat surface, a momentary pressure rise at the point of contact is created. As indicated in Fig. 1a, this pressure rise, Ap, is assumed to be a function of the drop diameter, D, the liquid density, , the acceleration of gravity g, and the distance the drop falls, d Determine a set of dimensionless parameters that describe this flow. graph of Fig. 1b. Use these results to predict the pressure rise associated with a 0.1-in - diameter drop of mercury (Peruny13.6par falling from a height of 2 in. . The result of experiments done with 0.2-in.- diameter water drops is indicated in the

Explanation / Answer

Answer: we know that v = sqrt(2gh)

rho = m/V

p/gh , D / d , p = 37.4 lb/ft2

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