Consider a 2000 N airplane with 50 m^2 wing-area in a level cruise flight: sea-l
ID: 2325878 • Letter: C
Question
Explanation / Answer
a) The lift is given by the relation,
L = 1/2 x rho x V^2 x A x CLalpha
Since the aircraft is banked at an angle of 10 deg the component of W reduces to W cos 10.
During ideal flight conditions the L = W,
1/2 x rho x V^2 x A x Cl alpha = m x cos 10
1/2 x 1.25 x 150^2 x 50 x CL alpha = 2000 cos 10 / 9.81
CL alpha = 2.85 x 10^-4
b) Since the flight maintains a level flight at the same altitude and under ideal conditions the load factor L / W is 1.
c) The required angle of attack for the ideal airfoil is given by,
CLalpha = 2 pi alpha,
So alpha = CL alpha / 2 pi
alpha = 2.85 x 10^-4 / 2 x 3.14 = 0.00004 rad or 0.002 deg
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