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In an effort to estimate the mean amount spent per customer for dinner at a majo

ID: 2507269 • Letter: I

Question

In an effort to estimate the mean amount spent per customer for dinner at a major Indianapolis restaurant, data were collected for a random sample of customers. The data (in dollars) is shown below.

81 49 45 70 52 50 50


50 78 68 84 78 51 71


64 72 70 84 75 47 82


67 79 64 72 61 74 44


70 90 54 63 86 83 77


74 47 82 52 72 73 79


48 77 56 77 40 58 79


72 84 84 54 46 83 87
8 We are 95% confident that the mean amount spent per customer for dinner is between $______ and $_____.
(Note: Use the Excel functions to compute the mean and standard deviation. Otherwise, you'd be wasting your time. And, don't round anything, except the final answer.)
a 66.1 74.1






b 63.7 71.2






c 58.1 68.4






d 52.7 63.4
















9 The following data have been collected for a sample from a normal population:




x








22








50








40








21








42








39








12








16
















The margin of error for a 95% confidence interval for the population mean is ______.

(Use your calculator to compute the mean and the standard deviation of the sample.) a 11.78







b 10.25







c 9.76







d 8.59

















10 In the previous question, to obtain a margin of error MOE = 4, the minimum sample size should be at least n = _______. Use the standard deviation from that sample (rounded to the nearest integer) as the planning value.

a 21







b 33







c 48







d 67

















11 Let In an effort to estimate the mean amount spent per customer for dinner at a major Indianapolis restaurant, data were collected for a random sample of customers. The data (in dollars) is shown below.

81 49 45 70 52 50 50


50 78 68 84 78 51 71


64 72 70 84 75 47 82


67 79 64 72 61 74 44


70 90 54 63 86 83 77


74 47 82 52 72 73 79


48 77 56 77 40 58 79


72 84 84 54 46 83 87
8 We are 95% confident that the mean amount spent per customer for dinner is between $______ and $_____.
(Note: Use the Excel functions to compute the mean and standard deviation. Otherwise, you'd be wasting your time. And, don't round anything, except the final answer.)
a 66.1 74.1






b 63.7 71.2






c 58.1 68.4






d 52.7 63.4
















9 The following data have been collected for a sample from a normal population:




x








22








50








40








21








42








39








12








16
















The margin of error for a 95% confidence interval for the population mean is ______.

(Use your calculator to compute the mean and the standard deviation of the sample.) a 11.78







b 10.25







c 9.76







d 8.59

















10 In the previous question, to obtain a margin of error MOE = 4, the minimum sample size should be at least n = _______. Use the standard deviation from that sample (rounded to the nearest integer) as the planning value.

a 21







b 33







c 48







d 67

















11 Let

Explanation / Answer

8) B


mean = 67.48


sd dev = 13.86


mean lies between ( 67.48 - 1.96 * 13.86/sqrt(56) , 67.48 + 1.96 * 13.86/sqrt(56) )


= ( 63.7, 71.2)


9) mean = 30.25


stdev = 13.17


error = 1.96 * 13.17/sqrt(8) = 9.76


hence answer is C



10) C 48


11) mean = 26


stdev = 9.61


mean lies between = ( 26 - 1.96 8 * 9.61/sqrt(5) , 26 + 1.96 8 * 9.61/sqrt(5))


= 17.6 , 34.4


answer is C


12) C


13) A

14) D

15)A

16) B


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