Three charged marbles are glued to a nonconducting surface and are placed in the

Question

Three charged marbles are glued to a nonconducting surface and are placed in the diagram as shown. The charges of each marble are q1 5.65 uc, q2 J 1.82 HC, and q3 74 HC. Marble q1 is a distance ri 3 3.00 cm to the left of the marble q2, while marble q3 is a distance r3 2.00 cm to the right of the marble q2, as shown. Calculate the magnitude of the electric field a distance r 3 00 cm to the left of the center marble. 3.2452e8 What is the electric field due to each individual marble? How do you find the total or "net" electric field when you have several electric fields? N/C 92 observation point Another marble is placed 1 cm to the le marble has a charge of 3.55 HC calculate magnitude and direction of the force on it. ft of the middle marble. If this new 2053.604 magnitude If you know the electric field how do you calculate the force on a charge in that electric field? Did you convert a of your values to SI units (meters kilograms, coulombs, seconds)? N direction right

Explanation / Answer

Sol.:-

E = kQ / d²
At the point in question, the field due to q1 is positive (to the right), due to q2 is negative (to the left) and due to q3 is positive (to the right). Then
E = 9.0 x 10^9 N·m²/C² * (5.65/(0.02m)² - 1.82/(0.01m)² + 1.74/(0.03m)²) * 1e-6C
E = 1.9275 x 10^7 N/C field at 1 cm left of center marble

For fourth marble:
F = q*E = 3.55 x 10^-6C * 1.9275 x 10^7N/C = 68.42 N
and the direction is "to the right."

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