the spaceship intergalactica lands on the surface of the uninhabited pink planet

Question

the spaceship intergalactica lands on the surface of the uninhabited pink planet, which orbits a rather average star in the distant garbanzo galaxy. a scouting party sets out to explore. the party's leader- a physicist, naturally- immediately makes a determination of the acceleration due to gravity on the pink planet's surface by means of a simple pendulum of length 1.37 m she sets the pendulum swinging, and her collaborators carefully count 108 complete cycles of oscillation during 215 s. what is the result?

Explanation / Answer

T = 2pi (L/g)^0.5

L = 1.37m
108T =215
T =215/108 = 1.99
Putting the values into the original expression, g = (2pi)^2 * L/T^2 )

=   ((2pi)^2 *1.37/(1.99)^2))

= 13.64 m/s^2

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