Can someone help me out with this question? 6. (10 points) Consider an uncharact

Question

Can someone help me out with this question? 6. (10 points) Consider an uncharacterized bacterial respiratory electron transfer chain. Preliminary work indicates that there are four electron carriers, termed I, II, III, and IV, whose oxidation states can be distinguished spectroscopically. In the presence of substrates and oxygen, three different inhibitors are found to block respiration, as shown in the table below (O means fully oxidized, R means fully reduced). What is the order of the carriers in the chain from substrates to O2 and where do the three inhibitors act? Electron Carriers Inhibitor

Explanation / Answer

now as we all know that, at the last, oxygen will be reduced with hydrogen and will make H2O. so it means reduction of oxygen molecule happened and it is its fully reduced form. so as per the details given in table, the fully reduced form will comes at last, and fully oxidized form will come first.

So...

the order will be as follow....

IV --------- I ----------II ------------ III

now as the table shows.... Inhibitor has been worked where the process happen in previous and next event....

suppose... in table... column IV of electron carrier shows the all oxidized and the same thing is shown in column I, but in 2nd raw the same column shows the progress from O to R. it means the inhibitor 1 was stopiing this reaction. accordingly in all reaction you can see in the table.

Inhibitor 1 > working on 1st reaction IV ------- I

Inhibitor 2 > working on 2nd reaction I - ------- II

Inhibitor 3 > working on third reaction II - ------- III.

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