s exist as complementary partners that carry out membrane fusions between approp

Question

s exist as complementary partners that carry out membrane fusions between appropriate vesidles and their target membranes. In certain cases, membrane vesicles destined to fuse contain both v- and t-SNAREs. You conduct a series of experiments to test how v- and t-SNAREs function by mating two strains of yeast. If the vesicles from the two strains fuse successfully, that activates an enzyme called alkaline phosphatase (AP), whose activity can be measured (in arbitrary units). In each trial, the two strains will express on their vesicles either no SNARES (:v- SNAREs only (v); t-SNARES only (t): or both v- and t-SNAREs (vt). After mating these strains, you measure the activity of alkaline phosphatase over three replicates. Your results for average values +- standard errors are listed in the 4h column of Table 1. (For this question, you might consider using a spreadsheet program like Excel or Google Sheets.) Table 1 Trial # | Strain 1 | Strain 2 | 90 AP activity, (normalized) | AP activity vt vt 50 +/-3 5 +- 3 vt 25 +-10 23 +/-8 4 +/-3 6 +/-2 4 +-2 20 +-6 18 +/-9 2 3 4 6 7 vt 10 vt A. (1pts) Which of these trials is a positive control for the experiment? Please briefly describe your reasoning. B. (2pts) Calculate the normalized alkaline phosphatase activity for trials 1-9 as a percentage of the positive control's average value, and write these values in the last column. (For example, if the positive control value is 6,000 + 200, and the measured value is 18,000 +/-600, you should enter 300% +/-10%.) C. (1 pts) For Trial #10, fill in the row to provide conditionsandpredictedmeasurements for a negative control. D. (1 pts) For Trial #11, fill in the row to provide predictedmeasurements for these conditions

Explanation / Answer

A) Trial #1 must be the positive control for this experiment because a positive control is a setup where we provide all the experimental requirement to obtain the best reaction/result/outcome. In the Trial #1, we have both the v- and t- SNAREs from both the strain 1 and 2.

Answer B) Normalized alkaline phosphatase activities for trials 1-9 are given below;

Trail 1 = 50+/-3 / 50+/-3 = 100 %

Trial 2 = 5+/-3 / 50+/-3 = 10% +/- 6%

Trail 3 = 25+/-10 / 50+/-3 = 50% +/- 10%

Trial 4 = 23+/-8 / 50+/-3 = 46% +/- 16%

Trial 5 = 4+/-3 / 50+/-3 = 8% +/- 6%

Trial 6 = 6+/-2 / 50+/-3 = 12% +/- 4%

Trial 7 = 4+/-2 / 50+/-3 = 8% +/- 4%

Trial 8 = 20+/-6 / 50+/-3 = 40% +/- 12%

Trial 9 = 18+/-9 / 50+/-3 = 36% +/- 18%

Answer C) For Trial # 10, conditions for the negative control must be ( Strain 1 as "-" and Strain 2 as "-"). and the predicted measurement must be somewhat similar to the Trial 6 and 7 ( 5+/- 2).

Answer D) For Trial # 11, predicted measurement must be somewhat to the conditions of Trail 3 and Trial 4.

so the measurement must be 24 +/- 9.

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.