After incubation, the number of positive (+) tubes in the test was 3, 1, 0 I 3(+

Question

After incubation, the number of positive (+) tubes in the test was 3, 1, 0 I 3(+) in the tubes inoculated with 1.0 ml:1 (+) tube in the series inoculated with 0.1 ml; 0 (+) tubes in the series inoculated with 0.01 ml]. The MPN table reports that a 3, 1, 0 score means that the number of bacteria in the sample is most probably 43/100 ml (if the series were inoculated with 10 ml, 1 ml and 0.1 ml). What is the number of bacteria in the sample based on your 6. Instead of 10 ml, 1 ml and 0.1 ml in an MPN series you use 1.0 ml, 0.1 ml and 0.01 ml. inoculation scheme? d) 430/100 ml e) 4300/100 ml a) 43/100ml b) 4.3/100 ml c) 0.43/100 ml 7. The lethal affect exerted on bacteria by small amounts of certain metals is called: a) oligodynamic action b) nascent action c) vesicant action d) mass action e) where's the action 8. Imagine that there is an organic compound that an organism requires for growth but which it cannot synthesize for itself and, therefore, must be provided in the growth medium. By definition this nutrient is called a: a) growth factor b) micronutrient c) non-essential organic compound e) trace element 9. Imagine that a culture of bacteria capable of synthsizing compatable solutes is growing ina solution with an optimal water activity for the population, but is then transferred to a more hypertonic solution. A typical response for these bacteria would be to a) increase the compatible solute concentration in the solution b) increase the compatible solute concentration in the cells decrease the compatible solute concentration in the solution c) d) decrease the compatible solute concentration in the cells e) decrease the compatible solute concentration in the solution and the cells 10. An agent is considered to be a(n) if it is applied to inanimate objectes. if it can be applied to living tissue but a(n) a) disinfectant b) antiseptic c) antiseptic d) disinfectant e) disinfectant sterilant sterilant disinfectant antiseptic inhibitor

Explanation / Answer

Hi Answer:

Q. 1. Answer is option E (All the above are direct counting methods)

Q.2. option A i.e 22 cells formula used is Final number of cells (N) = Initial number of cells (N ) X (2n) n = number of doublings

Q.3. option d (150000)

Q.4. option d (All the above)

Q.5. Option e (Non ionizing radiations uv.)

Q.6

Q.7. Option A (Oligodynamic action)

Q.8. Option A (Growth factor)

Q.9. Option

Q.10 Option A (Disinfactant & sterilent)

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