For a gene library, we can easily calculate the number of individual recombinant
ID: 261378 • Letter: F
Question
For a gene library, we can easily calculate the number of individual recombinant molecules required to represent an entire genome:
N = [ln (1-P)]/[ln (1-f)]
P – probability of complete coverage (99% or 0.99 confidence) N – number of individual clones required
f – proportion of genome in average fragment
The genome size is 5,000,000 kb. Your vector is a cosmid that can stably carry up to 30 kb. How many recombinant molecules would be required to represent the entire genome? SHOW YOUR WORK for this problem
Explanation / Answer
Probability of 0.99 and an average insert of 30kb,the recombination depends on size of choosen organism genome.
Genome size=5000000kb=5x109
Insert size=30kb=3x104
Probability 0.99
No of recombination in gene library id
N=[In(1-P)]/[In(1-f)]
N=In(1-0,99)/In(1-(3x104/5x109)
=In(0.01)/In(1-0.6x10-5)
=In(0.01)/In(0.999994)
=7.6x106 recombinants.
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