The frequency of the Hemoglobin A allele is 0.9. The heterozygote with the reces
ID: 265131 • Letter: T
Question
The frequency of the Hemoglobin A allele is 0.9. The heterozygote with the recessive allele, s, shows resistance to the malarial parasite. What is the frequency of the heterozygote for the pair As?Please show work. The frequency of the Hemoglobin A allele is 0.9. The heterozygote with the recessive allele, s, shows resistance to the malarial parasite. What is the frequency of the heterozygote for the pair As?
Please show work. The frequency of the Hemoglobin A allele is 0.9. The heterozygote with the recessive allele, s, shows resistance to the malarial parasite. What is the frequency of the heterozygote for the pair As?
Please show work. The frequency of the Hemoglobin A allele is 0.9. The heterozygote with the recessive allele, s, shows resistance to the malarial parasite. What is the frequency of the heterozygote for the pair As?
Please show work.
Explanation / Answer
So we are provided with P value = 0.9 that is frequency of dominant allele A.
Now the q value or recessive allele(s) frequency= 1- P
= 0.1
We know from Hardy Weinberg law that-
P2AA + 2pq (As)+ q2ss = 1
Here 2pq = frequency of heterozygote
Therefore 2pq( As) = 2× .9 × .1
= .18
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