Questions 64 to 67 are connected Zea mays is a diploid species with 10 pairs of
ID: 265890 • Letter: Q
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Questions 64 to 67 are connected Zea mays is a diploid species with 10 pairs of chromosomes in each somatic cell. How many chromosomes will be found per cell in each of the following chromosome mutants? 64) Trisomy? E) 21 A) 19 B) 22 65) Monosomy? E) 21 B) 22 C) 60 D) 30 66) triploid D) 30 E) 21 A) 19 C) 60 67) Tetrasomy E) 21 C) 60 D) 30 A) 19 68) Species I has 2n 12 chromosomes and species II has 2n-14 chromosomes. What would be the expected chromosome numbers in individual organisms with the following chromosome mutations? Allotriploidy including species I and II A) 12 or 14 D) 6 or 7 E) 20 and 30 B) 24 or 28 C) 19 or 20 69) These s semi-conservative. scientists conducted experiment with NI4 and N1s isotopes and discovered that DNA replica A) Watson and Crick D) Watson and Chargaff B) Meselson and Stahl C) Avery and McCathy E) Rosalind Franklin and Maurice Wilkins 70) This scientist injected mice with the two strains of bacteria, one virulent (S) and the other avirulern (R). The S bacteria strain killed mice whereas the avirulent R bacteria did not. When S strain was hea killed and mixed with R strain and injected to mice, it died. Thus the scientist discovered transformati A) Chargaff B) Rosalin C) Watson D) Griffith E) Crick 71) These evidence was available to Watson and Crick that helped them to discover the struct of DNA A) Rosalind Franklin X-ray diffraction studies B) Chargaff determination that the amount of A equals T and G equals C C) Linus Pauling deduce the structure of an alpha helix in protein D) all of the above ) none of the above 72) A virus contains 10% adenine, 10% uracil, 41% guanine, and 39% cytosine. A) Double-stranded DNA B) Single-stranded DNA D) Single-stranded RNAE) Chloroplast DNA This virus is: C) Double-stranded RNA, two types of amino acids are found in the amino terminal region of histone molecu A) Leucine and Isoleucine B) glycine and lysine D) Tryptophan and glycine E) arginine and lysine C) serine and tyrosineExplanation / Answer
Zea mays:
2n = 20
n = 10
64. Trisomy = One extra copy of a chromosome = 2n + 1 = 21
65. Monosomy = Absence of a chromosome = 2n - 1 = 19
66. Triploid = 3n = 30
67. Tetrasomy = 2n + 2 = 22
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