Using this code table, consider the following template strand of a DNA molecule
ID: 270230 • Letter: U
Question
Using this code table, consider the following template strand of a DNA molecule Second base UGU-Cysteine Uuun Phenyl- UUCJ alanine UCU UCC -Serine UCA UAU UAC yrosine UAA Stop codon UGA Stop codon UAG Stop codon UGG Tryptophan UUA Leucine CAU 1-Histidine cGC CAC CGU CUU CUC Leucine CUA CUG CCU CCC Proline CCA CCG Arginine as)-Glutamine CGA CAG AGUSerine AAU AAC AUU AUC Isoleucine ACC AUA AUG ACU Asparagine AGC Threonine ACA Methionine ACG (start codon) AGA AGG Arginine AAG Lysine GCU GUU GUC Valine GUA GUG GAUAspartic GGU GACJ acid GGCGlycine GCA Alanine GCG GAA 1 Glutamic GGA GAG acid Template strand: 3' TGATGGCCGGGGGCC 5' 17.) How many amino acids would be coded for by this sequence? 18) The first and last amino acids produced by this mRNA sequence would be, respectively,Explanation / Answer
17. Since there are 15 nucleotides or 5 codons in the strand, so 5 amino acids will be coded by the given template sequence.
18. The first amino acid is coded by 3' TGA 5' which is transcribed to 5' ACU 3' that codes for amino acid - Threonine
The last amino acid is coded by 3' GCC 5' which is transcribed to 5' CGG 3' that codes for amino acid - Arginine.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.