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I need them answered ASAP, please show all the work!! and I need all these diffe

ID: 272894 • Letter: I

Question

I need them answered ASAP, please show all the work!! and I need all these different pages solved!! thank you in advance, I have two other questions I have posted, please if any body can answer these I will appreciate it too! thank you!! QUES. 7-9. In Drosophila, you cross pure breeding ebony body (e), long winged (s+ flies with pure breeding tan body (e+), short winged (s) flies. All Fl flies have tan body and long wings. You cross F1 females to ebony, short winged males. The following phenotypes are observed among 1000 offspring 159 ebony short; 338 ebony long: 161 tan long; 342 tan short. 7. The parental type gametes produced by the Fl individuals were a) et st&es; b) e+ s, est, etst, es c)est & es d)ets& est e) et st 8. The gamete received from the F1 females by tan long offspring is a) etst b) est c)ets d)es e) ete+ stst 9. The map distance between the e and s loci is a) 70 b) 68 c) 38 d) 32 e) 20. 10. In a test cross of a double heterozygote, each of the recombinant type gametes occurs at a frequency of 15%. The expected frequency of each of the parental type gametes is a) 15% b) 20% c) 35% d) 45% e) 50%. 2. Phenylketonuria (PKU) is a recessive genetic disease caused by the p allele. Based on our discussion of this disease in lecture, which of the following statements is true a) a pp individual will always exhibit the effects of PKU, regardless of the diet that individual is raised on b) a PP will exhibit the effects of PKU if raised on a diet high in phenylalanine c) a pp individual will not exhibit the effects of PKU if raised on a diet low in phenylalanine d) the genotype of a pp individual will change to Pp when raised on a diet low in phenylalanine e) the genotype of a pp individual will change to Pp when raised on a diet high in phenylalanine 13. Which of the following would be an appropriate measure of the phenotypic variation of a trait in a population a) the mean of the trait in the population b) the standard deviation of the trait c) the heritability of the trait d) the allele frequency of genes affecting the trait. 14. Evolutionary change of a trait in a population under the effect of selection can occur only when a) VE>0 b) h2>0 c) h2- 0 d) VE- 0

Explanation / Answer

1) F1 female genotype is - es+/e+s .

parental type gamate produced by f1 is- es+ and e+s. option D.

2) option A. e+s+

3) 159+161 /1000 = 320/1000 = 32% or 32 mu. option D.

4) each recombinant is 15% means two recombinants = 30 % total recombinants.

70% is total parental genotype . so 35% is each paarental genotype. option C.

P = parental, R = recombinant.

es e+s e+s/es(342) P1 es+ es+/es(338) P2 e+s+ e+s+/es(161)R1 es es/es(159)R2
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