In squirrels, the gray allele (G) is dominant to the brown allele (g) at the coa

Question

In squirrels, the gray allele (G) is dominant to the brown allele (g) at the coat color locus. A population of 240 squirrels in Pellie Park was scored for the coat color locus. The frequency of the gray allele was found to be 0.56. Due to construction at LSU, 45 LSU squirrels migrated to Pellie Park. The frequency of the gray allele in the LSU squirrels was 0.17. The squirrels mated randomly to form a progeny generation at Pellie Park. Assuming that no further migration occurred and that all other conditions for Hardy-Weinberg equilibrium were met, what is the frequency of the gray allele in the progeny generation at Pellie Park? Round your answer properly to 4 DECIMAL DIGITS!

Explanation / Answer

In migration , a large population consist of a propirtion of m of new immigrants in each generation. The remainder 1-m being native. Let the frequency of certain allele be qm among the immigrants and qo among native. Then the frequency of gene in mixed population q1 will be

q1 = m(qm -qo) + qo

In this question , native of pellie park is 240 squirrels and 45 migrated to pellie park so total population will be 285.

Among them, proportion of native = 240/285 = 0.84

Proportion of immigrants = 45/285 = 0.16

So, m = 0.16

qm = 0.17

qo = 0.56

Frequency of allele in mixed opulation will be

q1 = 0.16 (0.17-0.56) + 0.56

q1 = -0.0624 +0.56

q1 = 0.4976

In next generation ,there is random mating, no migration , no selection so follow hardy weinberg equilibrium and the frequency of grey allele in progeny generation remain same as parent generation means the allele frequency will be 0.4976.

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