In a parental cross between a true breeding female fly with NortusDigitatum wing

Question

In a parental cross between a true breeding female fly with NortusDigitatum wings and a true breeding male fly with wild type wings, all F1 offspring have NortusDigitatum wings. When an F1 female fly mates with F1 male, the following counts are produced in the F2 generation: Female, Wild-type: 1221 Male, Wild-type: 1251 Female, NortusDigitatum: 3757 Male, NortusDigitatum: 3798 These results suggest that:

A. The mode of inheritance for the NortusDigitatum wing type is autosomal dominant.

B. The mode of inheritance for the NortusDigitatum wing type is autosomal recessive.

C. The Chi-Squared Test for goodness of fit when ignoring sex is 1.22249.

D. The p-value for the Chi-square goodness of fit when considering sexes separately is 0.4229.

E. Flies cannot produce that many offspring.

Explanation / Answer

A. The mode of inheritance for Nortusdigitatum wing type is autosomal dominant. This is so because in heterozygous condition (F1 generation), all progeny had Nortusdigitatum wing type. Also the phenotypic ratio of in the F2 generation is (3757+3798):(1221+1251) = 3:1 = Nortusdigitatum:wild type. This is typical of a autosomal dominant trait inheritance.

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