Can someone help me on this question? only problem i\'m having trouble with Inst

Question

Can someone help me on this question? only problem i'm having trouble with

Instructions: This homework set has 3 Problems. The total credit for this homework set is 20. Please write down your name, ID, and section number on the upper-right comer ot the paper. Please show your work! Computer upgrade times (in minutes) are being evaluated. Samples of five observations each have been taken, and the results arc as listed. Determine upper and lower control limits for mean charts. Determine upper and lower control limits for range charts. Decide if the process is in control.

Explanation / Answer

1 2 3 4 5 6 X - Bar Range 79.2 80.5 79.6 78.9 80.5 79.7 79.733 1.600 78.8 78.7 79.6 79.4 79.6 80.6 79.450 1.900 80.0 81.0 80.4 79.7 80.4 80.5 80.333 1.300 78.4 80.4 80.3 79.4 80.8 80.0 79.883 2.400 81.0 80.1 80.8 80.6 78.8 81.1 80.400 2.300 399.800 9.500 X-Bar is average of observations of that sample Eg - Sample 1 = (79.2 + 80.5 + 79.6 + 78.9 + 80.5 + 79.7)/6 = 478.4 / 6 = 79.733 Range is difference between maximum value and minimum value of the observations Eg Sample 1 = 80.5 - 78.9 = 1.600 X - Double Bar = X - Bar / No of samples = 399.80/5 = 79.96 UCL = X-Double Bar + A2 * Range Bar LCL = X-Double Bar - A2 * Range Bar A2 value for 6 observations = 0.48 UCL = 79.96 + 1.90 * 0.48 = 79.96 + 0.912 = 80.872 LCL = 79.96 - 1.90*0.48 = 79.96 - 0.912 = 79.048 R - Bar = Range / No of samples = 9.5 / 5 = 1.90 UCL = D4 * Range Bar LCL = D3 * Range Bar D3 value for 6 observations = 0 D4 value for 6 observations = 2.00 UCL = 1.90 * 2 = 3.80 LCL = 0.515 * 0 = 0

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