iii) Your friend is working in a biotech company that is trying to identify chan
ID: 276813 • Letter: I
Question
iii) Your friend is working in a biotech company that is trying to identify changes in proteins that can cause disease. They isolate a Cdc2 protein from a disease cell, and determine the amino acid sequence of Cdc2 in the diseased cell. The figure below shows a portion of the normal Cdc2 protein from humans and yeasts S. pombe and S. cerevisiae. The bottom line of the Figure has the sequence from the Cdc2 isolated from the diseased cell. Sequences identical between the human and fungal proteins have been boxed. #1 #2 #3 #4 human FGIPIRVYTHEVVTLWYR S. pombe FGVPLRNYTHEIVTLWYR S. cerevisiae FGVPLRAYTHEIVTLWYR... disease cell... FAIPIRVYDHEVITMWYR Four amino acid changes are observed in the Cdc2 protein from human diseased cells: #1 is G to A, #2 is T to D, #3 is V to 1, and #4 is L to M. These changes are indicated with arrows on the Figure above. Of the four changes, which one do you predict is the most disruptive to Cdc2 function? Explain your answer. (5 points)Explanation / Answer
1st mutation: G to A. both glycine and alanine are amino acids with a nonpolar side chain.
2nd mutation: T to D. threonine is an amino acid with an uncharged polar side chain, whereas aspartate is an amino acid with a negatively charged polar side chain.
3rd mutation: V to I. both valine and isoleucine are amino acids with a nonpolar side chain.
4th mutation: L to M. both leucine and methionine are amino acids with a nonpolar side chain.
of the above mutations, 1st, 3rd and 4th mutations resulted in the change to a similar amino acid. whereas 2nd mutation led to a change in the type of amino acid. therefore, 2nd mutation (T to D) is the more disruptive.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.