ignment-Responses/submit?dep: 18129317#04 My No Insurance status-covered (C) or
ID: 3064891 • Letter: I
Question
ignment-Responses/submit?dep: 18129317#04 My No Insurance status-covered (C) or not covered (N)-is determined for each individual arriving for treatment at a hospital's emergency room. Consider the chance experiment in w determination is made for two randomly selected patients 2 (C, N), (N, C), and O4-(N, N). Suppose that probabilities are p(01) 0,81, p(02) 0.09, p(03)-0.09, and roo-001 the event that at most one patient is not covered? A {(C,N), (N, C), (N, N)} o AF((C, C), (C, N), (N, C)) What is P(A)? P(A) (b) What outcomes are contained in B, the event that the two patients have the same status with respect to coverage? o B ((C, C), (C, N)) 8-{(C, N), (N, C)} B-: {(C, N), (N, N)} the empty set What is P(B)? P(B) 0.19 Submit Ans My Not 3/3 points | Previous Answers PODStat4 6.E.022Explanation / Answer
Solution: (a) What outcomes are contained in A, the event that at most one patient is not covered.
Answer: A={(C,C),(C,N),(N,C)}
What is the P(A)?
Answer: P(A)=0.81+0.09+0.09=0.99.
(b) What outcomes are contained in B, the event that the two patients have the same status with respect to coverage?
Answer: B={(C,C),(N,N)}
What is P(B)?
Answer: P(B)=0.81+0.01=0.82
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