The question: Catabolism of the amino acid leucine which takes place in the mito

Question

The question:

Catabolism of the amino acid leucine which takes place in the mitochondrial matrix yields the following:

3 acetyl coa, 1 NADH + H+, 1 FADH2. Calculate the number of ATP molecules that would be formed by the total oxidation of these products to co2 and h2o in a tightly coupled mitochondrial suspension supplied with o2 and the necessary coenzymes and catalysts. Provide an itemized indication of the source of the ATPs formed.

My answer:

1 NADH & H+= 2.5 ATP

1 FAD= 1.5 ATP

Each Acetyl CoA:

3 NADH (isocitrate DH, alpha keto. DH, Malate DH)= 2.5* 3= 7.5

1 FADH2 (succinate DH) = 1.5 ATP

1 GTP (succinyl coa synthase) = 1 atp

=10 *3 acetyl coa= 30 + 4 [from above] = 34 ATPs made

is this correct??

Explanation / Answer

Answer:

Yes, you are correct.

Each Acetyl Coa forms 10 ATP in total as it undergoes oxidation through Krebs cycle

3 NADH=7.5 ATP

1 FADH=1.5 ATP

1 GTP= 1 ATP

Therefore 1 Acetyl Coa= 10ATP

Total ATP formed = 34 ATP

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.