On the planet Susru, there are three types of bears; those who like honey-nut ch

Question

On the planet Susru, there are three types of bears; those who like honey-nut cheerios, those who like multi-grain, and those who like plain cheerios. The phenotype is determined in an epistatic way by two loci: HNNT, with alleles H (dominant) and h (recessive), and MLTGRN, with alleles M (dominant) and m (recessive). In a cross of a HHMM bear and an hhmm bear, and the F1s like honey-nut. A cross of two F1 bears produces the following sums two-locus genotype counts: All F2 bears with at least one H allele: 1300. All F2 bears with at least one M allele but no H alleles: 325. What number of F2 bears with the hhmm genotype would produce an F2 data set that is consistent with a dominant mode of inheritance at the 1% level of significance (Hint: Think Chi-square)?

Explanation / Answer

Parents HHMM x hhmm produces HhMm F1 progeny HhMm x HhMm produces HHmm, HhMm, hhMM progeny . The gametes here would be Hm, hM . This is because , the values for F2 progeny is given for atleast one H allele 1300 . and atleast one M allele but no H alleles is 325. If the gametes area HM and hm there wont be dominant M allele alone always it will be present along with H allele. The degree of freedom is 1. If this mode of inheritance to be followed there should not be any hhmm genotype present or only least number of hhmm genotypes must be present.

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