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Moon Activity THESE ARE THE VALUES I GOT FROM THE EXCERCISE BEFORE THIS ONE some

ID: 283885 • Letter: M

Question

Moon Activity

THESE ARE THE VALUES I GOT FROM THE EXCERCISE BEFORE THIS ONE some valeus might be needed to calculate the above:

the Crater(TERMINATOR) name seems to be in Sinus meddi/ Sinus aestuum sector and the crater name is Crater Manilus. Crater is nearly circular in shape or appearence. This crater lies in the equator of the moon. at 0 latitude and 0 longtitude.

i have made this picture on paper. It take 8cm of my paper to complete.

radius of moon is = 1734km

now the scale factor= 1734km/4cm= 433.5 Km/cm

distance from the tereminator to the top of the feature is D= 2.5km shadow height s = 0.5km

now real distance D = f*d = 433.5* 2.5 = 1083.75km

shadow length S = f* s = 433.5*0.5 = 216.75 km

SO the true height of mountain H = S*D/R = 216.75 *1083.75/1734 = 135.46 km

Explanation / Answer

Let suppose the length of the object L=1.3cm

Now we need to calculate the height of the object

height of the object=L*L/R

R= radius of the object=2.3cm

Now height of the object=1.3*1.3/2.3

=0.7cm

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