can u solve # 78 pleas Vertical Motion In Exercises 77-80, use a(t) = -32 feet p

Question

can u solve # 78 pleas

Vertical Motion In Exercises 77-80, use a(t) = -32 feet per second per second as the acceleration due to gravity. (Neglect air resistance.). A ball is thrown vertically upward from a height of 6 feet with an initial velocity of 60 feet per second. How high will the ball go? Show that the height above the ground of an object thrown upward from a point s0 feet above the ground with an initial velocity of v0 feet per second is given by the function f(t) = - 16 t2 + v0 t + s0. With what initial velocity must an object be thrown upward

Explanation / Answer

initial velocity=v0

acceleration=-9.81m/s=-32.174ft/s^2

so distance travelled by body=v0*t+(-32.174)t^2/2

=v0t-16t^2

so total height from the ground=s0+v0t-16t^2

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