-- To find a position vector between two arbitrary points. As shown, two cables
ID: 2844845 • Letter: #
Question
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To find a position vector between two arbitrary points. As shown, two cables connect three points. C is below A by a distance Cz = 2.50 ft and connected to A by a cable 7.93 ft long. Cable AC forms an angle beta = 35.0degree with the positive y axis. B is 8.70 ft above C and the distances Bx and By are 7.00 ft and 4.10 ft. respectively. Using the dimensions in the figure, find the position vector from A to B in component form. Express your answers, separated by commas, to three significant figures. For the position vector found in Part A. find the unit direction vector acting in the same direction. Express your answer in component form. Express your answers, separated by commas, to three significant figures. The length of cable AC is 7.93 ft . and the cable forms the angle beta = 35.0degree with the y axis. Given this information and the dimensions provided in the figure, find the position vector from A to C Express the position vector in component form. Express your answers, separated by commas, to three significant figures. Part D - Position vector from B to C Find the position vector from B to C Express your answer in component form. Express your answers, separated by commas, to three significant figures. Submit Hints My Answers Give Up Review Part Part E - Tension in the cable A cable is attached between B and C The cable is attached in such a way that it has a tension of Tbc along its length. The tensile force will attempt to pull B toward C The force exerted on B has a z component with a magnitude of 10 lb . What is the magnitude of the tension in the cable. Tap? Express your answer to three significant figures and include the appropriate units.Explanation / Answer
C) 3.80, 6.50, -2.50
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