You are the game warden in your town and are responsible for stocking the local
ID: 2845130 • Letter: Y
Question
You are the game warden in your town and are responsible for stocking the local lake
prior to the opening of the fishing season. The average depth of the lake is
20 feet. Your plan is to stock the lake with 1 fish per 1000 cubic feet, and have
approximately 25% of the original fish population remaining at the end of the season.
What is the maximum number of fishing licenses that can be sold if the average catch is
20 fish per license?
The points on graph are from P0 to P8.
It reads "Coordinate spacing = (x(i+1) - xi) = 200 Ft.
Also, H = (b - a) /n = 200 Ft. Where n = 8.
Thanks in advance!
You are the game warden in your town and are responsible for stocking the local lake prior to the opening of the fishing season. The average depth of the lake is 20 feet. Your plan is to stock the lake with 1 fish per 1000 cubic feet, and have approximately 25% of the original fish population remaining at the end of the season. What is the maximum number of fishing licenses that can be sold if the average catch is 20 fish per license?Explanation / Answer
(200/3) * (0 + 4(200) + 2(400) + 4(600) + 2(800) + 4(1000) + 2(1200) + 4(1400) + 1600) = 1,280,000 ft^2
Given average depth was 20ft. So...
20 * 1,280,000 = 25,600,000 ft^3 = volume
1 fish per 1000 cubic feet
25,600,000 / 1000 = 25,600 fish in the lake.
25% of 25,600 = 6400 = the amount of fish that need to remain.
75% of 25,600 = 19,200 = the amount of fish to be fished out.
Average catch is 20 fish per person, so..
19200 / 20 = 960 licenses per season allowed
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