A pair of closely spaced parallel conducting plates, charged with equal and oppo

Question

A pair of closely spaced parallel conducting plates, charged with equal and opposite electric charges, produces a uniform electric field in the region between them. In designing a cutting-edge device that will revolutionize the electronics industry, you set up such a pair of plates with a separation of 0.821 mm between them and charge them so that the direction of the electric field in their interior region is from plate A to plate B. Your idea requires that electrons, when released from rest at one of the plates, reach the other plate at the speed of 1.43% of the speed of light. (The speed of light is c = 3.00 A pair of closely spaced parallel conducting plates, charged with equal and opposite electric charges, produces a uniform electric field in the region between them. In designing a cutting-edge device that will revolutionize the electronics industry, you set up such a pair of plates with a separation of 0.821 mm between them and charge them so that the direction of the electric field in their interior region is from plate A to plate B. Your idea requires that electrons, when released from rest at one of the plates, reach the other plate at the speed of 1.43% of the speed of light. (The speed of light is c = 3.00

Explanation / Answer

V= 1/2mv^2 /q

V=1/2 *(9.11*10^-31) *(4 167 115^2) / (1.6*10^-19)

E= V /d
Plug in your value of V and d in meters (convert it from .821mm)

Should work.

And for plate, you need direction does it give you any direction, or stay anything about a force or voltage acting on it. You have to remember that A to B means A is positive and B is negative. An electron needs to accelerate to reach such speeds from rest - its speed. Only way it can rest by it self is if it is released to the positive plate, unless another force is acting on it. I would say its B-A. If it goes against the negative -positive trajectory, than work must be done by some voltage or force.

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