For questions 1 and 2, I just need to find the standard deviation from the infor

Question

For questions 1 and 2, I just need to find the standard deviation from the information given.

But for Question 3, I do need a solution to the problem overal..

Thank you, fast, detailed and handwritten responses preferred. 100% rating w/ pts awarded within 12 hrs of answer submission.

A teenager is trying to get a driver's license. Let X denote the number of tries he needs to pass the road test. Given that his probability of passing the exam on any given attempt is 0.10. So p = 0.10 Then X follows a geometric distribution with probability density function is given below. px (k, p) = (1 - 0.10)k-1 0.10, k = 1, 2, We have to find the expected number of attempts he is likely to require before he gets his license. We know that the mean of a geometric distribution is given by 1/p. So the expected number of attempts he is likely to require before he gets his license, 1/p = 1/0.10 = 10 Therefore, there is 10 expected numbers of attempts he is likely to require before he gets his license. When a machine is improperly adjusted, it has probability 0.15 of producing a defective item. Each day; the machine is run until three defective items are produced. When this occurs, it is stopped and checked for adjustment. We have to find the probability that an improperly adjusted machine will produce five or more items before bemg stopped. Let X be the random variable that denote the trial at which the three defectives are produced occurs. Then X follows a negative binomial distribution with probability density function is given below. px(k) = ( )pr (1 - p)k - r Let p denote the probability of producing a defective item. Given p = 0.15 Since we are waiting for the third defectives to be produced, r = 3 Probability that an improperly adjusted machine will produce five or more items before being stopped is obtained below. P(X 5) = 1 - P(X

Explanation / Answer

1. mean = 1/p=10.

s.d = root{[1-p*p]/p*p.}=9.487.

2.s.d = n*p*q=0.798.

3.

it starts like this.

x is the toss when 2nd head turns up.

it can take any value from 2 to infinity.

probability that x=2 is 1/4.

and x=3 is 1/8*2=1/4.

x=4 is 3/16. and so on.

so he manipulated the values so that 2 occurs 25 times , 4 occurs 16 times etc. so , he did not do the assignment faithfully.

sorry i could'nt handwrite, i dont have a camera. please rate my answer. i hope u uunderstand.

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