A volleyball is hit when it is 4 ft above the ground and 12 ft from a 6-ft-high

Question

A volleyball is hit when it is 4 ft above the ground and 12 ft from a 6-ft-high net. It leaves the point of impact with an initial velocity of 50 ft/sec at an angle of 27 degree and slips by the opposing team untouched. The acceleration due to gravity is g = 32 ft/sec^2. Answer the following questions. Find a vector form for the path of the volleyball. How high does the volleyball go, and when does it reach maximum height? Find the range and flight time. When is the volleyball 7 ft above the ground? How far (ground distance) is the volleyball from where it will land? The ball reaches a height of seven feet at seconds. The volleyball is feet from where it will land the first time it passes seven feet, and feet from where it will land the second time. Suppose that the net is raised to 8 ft. Will the ball still clear the net?

Explanation / Answer

A volleyball is hit when it is 4 ft above the ground and 12 ft from a 6-ft-high

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