Need help on these three calculus problems: For part C I figured out all of the

Q: Need help on these three calculus problems: For part C I figured out all of the

d) We have velocity function as v(t) = 4t^3 -10 Now when particle moves in postive direction it means that v(t)> 0 => 4t^3 -10 > 0 => 4t^3 > 10 => t^3 > 10/4 => t^3 > 5/2 => t> (5/2)^(1/3) In interval notation t = ( (5/2)^(1/3) , infinity) In decimal we have t= (1.35721, infinity)

ID: 2864094 • Letter: N

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Need help on these three calculus problems:

For part C I figured out all of the portions except I am so stuck on part D of this particular problem. All of the other problem was relatively easy, I just can't figure out what part D is to save my life. Any help would be appreciated.

BB WebWork - 2016Summer WeBWorK: Abramson_MA xBring Me The Horizon P2016SUMMERA-X-MAT26C Chegg Study | Guided Sol x c https://webwork asu.edu/webwork2/Abramson-MAT 265 ONLINE-A Summer-2016/Section 23/24/?key-PpLWPDCiGDVhDsefayNEkFV66ZjpcCsS8effectiveUser=at allir ( WeBWorK MAA Logged in as atwallin Log Out MATHEMATICAL ASSOCIATION OF AMERICA Kwebworkabramsonmat 265online a summer 2016 section 2.3 24 MAIN MENU Courses Homework Sets Section 2.3: Problem 24 Section 2.3 Problem 24 User Settings Previous Problem List ious Problem List Next Grades (1 point) At what point does the normal to y--1-3r + 4x2 at (1,0) intersect the parabola a second time? Problems The normal line is perpendicular to the tangent line. If two lines are perpendicular their slopes are negative reciprocals -- i.e. if the slope of the first line is m then the slope of the second line is -1/m Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 V Note: You can earn partial credit on this problem Preview My Answers Submit Answers You have attempted this problem 0 times You have unlimited attempts remaining Email instructor I'm Cortana. Ask me anything 0 6:21 PM 5/27/2016

Explanation / Answer

We have velocity function as

v(t) = 4t^3 -10

Now when particle moves in postive direction it means that v(t)> 0

=> 4t^3 -10 > 0

=> 4t^3 > 10

=> t^3 > 10/4

=> t^3 > 5/2

=> t> (5/2)^(1/3)

In interval notation t = ( (5/2)^(1/3) , infinity)

In decimal we have t= (1.35721, infinity)

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Need help on these three calculus problems: For part C I figured out all of the

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