Urban Community College is planning to offer courses in Finite Mathematics, Busi
ID: 2869012 • Letter: U
Question
Urban Community College is planning to offer courses in Finite Mathematics, Business Calculus, and Computer Methods. Each section of Finite Math holds 40 students and earns the college $1000 revenue per student. Each section of Business Calculus holds 40 students and earns the college $1500 per student in revenue. Each section of Computer Methods holds 10 students and earns the college $2000 per student. Assuming the college can offer a total of six sections, wishes to accommodate 210 students and wishes to bring in $260,000 in total revenues from these courses, how many sections of each course should it offer? You may solve the system using technology, but the answer must be inerpreted in the context of the problem (i.e. Answer the question that is asked). You must also so the setup of your 3x3 linear system of equations with your variables clearly defined.
Explanation / Answer
Let the college have M sections of Finite Math.
So Total number of Finite math students =40M
And the revenue from Finite Math student is $40000M
Let the college have B sections of Business Calculus.
So total number of Business Calculus students=40B
And the revenue from Business Calculus students is $60000B
Let the college have C sections of computer Methods.
So total number of Computer Methods students=10C
And the revenue from Computer Methods students is $20000C.
So the total number of sections is given by: M+B+C=6
So the total number of students is given by: 40M+40B+10C=210 ===>4M+4B+C=21
Total revenue is given by: 40000M+60000B+20000C=260000===>2M+3B+C=13
Solving these three equations, we get: M=3,B=2,C=1
So college offers 3 sections of Math,2sections of business and 1 section of computer
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