A canyon is 2100 meters deep at its deepest point. A rock is dropped from the ri
ID: 2873258 • Letter: A
Question
A canyon is 2100 meters deep at its deepest point. A rock is dropped from the rim above this point. Write the height of the rock as a function of time t in seconds. (Use -9.8 m/s2 as the acceleration due to gravity.)How long will it take the rock to hit the canyon floor?
A canyon is 2100 meters deep at its deepest point. A rock is dropped from the rim above this point. Write the height of the rock as a function of time t in seconds. (Use -9.8 m/s2 as the acceleration due to gravity.)
How long will it take the rock to hit the canyon floor?
How long will it take the rock to hit the canyon floor?
Explanation / Answer
distance travelled = 0.5*g*t^2
= -0.5*9.8*t^2
= -4.9t^2
so,
height of the rock as a function of time t = 2100 - 4.9t^2
How long will it take the rock to hit the canyon floor?
ans:
to hit the canyon floor, height = 0
so,
2100 - 4.9t^2 = 0
=> t = 20.70 sec
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