Find a vector equation and parametric equations for the line. (Use the parameter

Question

Find a vector equation and parametric equations for the line. (Use the parameter t.) The line through the point (0, 12, -9) and parallel to the line x = -1 + 3t, y = 6 - 3t, z = 3 + 7t r(t) = (x(t), y(t), z(t)) = () Find parametric equations for the line. (Use the parameter t.) The line through the points (0, 1/2, 1) and (5, 1, -2) (x(t), y(t), z(t)) = () Find the symmetric equations, x - 5 = 2y-2= z + 2 2x - 2 = y - 5/5 = z + 2/-3 5 + 5x = l + y/2 = -2 - 3z x - 5/5 = 2y - 2 = z + 2/-3 x + 2/-3 = 2y - 2 = z - 5/5

Explanation / Answer

1)direction vector of given line =-1+3t ,y=6-3t,z=3+7t is <3,-3,7>

direction vector of required parallel line =<3,-3,7>

vector equation of line with direction vector <3,-3,7> and passing through (0,12,-9) is

r(t)=(0,12,-9)+t<3,-3,7>

r(t)=<0+3t,12-3t,-9+7t>

r(t)=<3t,12-3t,-9+7t>

(x(t),y(t),z(t))=(3t,12-3t,-9+7t)

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.